I, for one, don't understand the question . Is it the hypontenuse (longest or 45° side) of the triangles formed by the 45° sides?
or the 2 equal short ones that you seek?
If so Pythagora's theory states that the square of the Hypotenuse is equal to the sum of the squares of the other 2 sides in a right triangle.
So .164 x .164 = .026986 and .026986/2=.013493 sq.rt. of which is .11615937 or .116 so the triangles each have 2 equal .116 sides and the 3rd (hyp.) is .164
I also have no idea what the dim. .748 is, represented by the -C- in a box under it.
or the 2 equal short ones that you seek?
If so Pythagora's theory states that the square of the Hypotenuse is equal to the sum of the squares of the other 2 sides in a right triangle.
So .164 x .164 = .026986 and .026986/2=.013493 sq.rt. of which is .11615937 or .116 so the triangles each have 2 equal .116 sides and the 3rd (hyp.) is .164
I also have no idea what the dim. .748 is, represented by the -C- in a box under it.
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