For a .002 interference, you'd probably want to expand it .004 to make sure you got it on. You only get one chance.
steel fas a coefficient of expansion of 6.7 x 10 to the -6, or .0000067 in/in deg f
So for initial bore of .666 in circumference is .666 x pi = 2.0923 (that size is the devil to machine)
For expanded di of .670, circumference is .670 x pi = 2.1049
delta cir =2.1049 - 2.0923 = 0.0126
for expansion, delta L /L = coef of expansion x delta temp
0.0126 / 2.0923 = .0000067 x delta T
or delta T = 900 degree farenhiet over room temperature
Should be doable with a propane torch.
Cooling the lead screw wouldn't do much, you might drop it from say 70 to freezer temp say 20 f or delta t of 50 It would help but would only shrink 0.00022 in dia.
Check the math but it should work.
This was a smaller bore so less expansion but only a 1 thou interference, I was afraid of breaking the gear when it cooled. At blue temperature on the gear it literally fell on to the shaft.
steel fas a coefficient of expansion of 6.7 x 10 to the -6, or .0000067 in/in deg f
So for initial bore of .666 in circumference is .666 x pi = 2.0923 (that size is the devil to machine)
For expanded di of .670, circumference is .670 x pi = 2.1049
delta cir =2.1049 - 2.0923 = 0.0126
for expansion, delta L /L = coef of expansion x delta temp
0.0126 / 2.0923 = .0000067 x delta T
or delta T = 900 degree farenhiet over room temperature
Should be doable with a propane torch.
Cooling the lead screw wouldn't do much, you might drop it from say 70 to freezer temp say 20 f or delta t of 50 It would help but would only shrink 0.00022 in dia.
Check the math but it should work.
This was a smaller bore so less expansion but only a 1 thou interference, I was afraid of breaking the gear when it cooled. At blue temperature on the gear it literally fell on to the shaft.
Free advice is worth exactly what you payed for it.
Greg
Greg